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If you have a dimension where each leaf member corresponds to 1 row of menu time data, that will permit percentile analysis. For example, if each leaf member of [Menu] has a single row, the 80 percentile value would be like: ([Measures].[MenuDuration], Order([Menu].[MenuID].Members, [Measures].[MenuDuration], BASC) .Item(Int(((4 * Count([Menu].[MenuID].Members)) - 1) / 5)).Item(0)) - Deepak Deepak Puri Microsoft MVP - SQL Server *** Sent via Developersdex http://www.developersdex.com *** |
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If you have a dimension where each leaf member corresponds to 1 row of menu time data, that will permit percentile analysis. For example, if each leaf member of [Menu] has a single row, the 80 percentile value would be like: ([Measures].[MenuDuration], Order([Menu].[MenuID].Members, [Measures].[MenuDuration], BASC) .Item(Int(((4 * Count([Menu].[MenuID].Members)) - 1) / 5)).Item(0)) - Deepak Deepak Puri Microsoft MVP - SQL Server *** Sent via Developersdex http://www.developersdex.com *** |
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