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MDX calculated members in Columns

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Milind
 
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Default MDX calculated members in Columns - 12-02-2005 , 05:51 PM






Hi

I have a 4 dimensions Person, Question, Client, QuestionSet and a
measure Encounter

I am looking for an output like the below

Answer Six Twelve
_________ ______ _____
Constantly 5 7
Rarely 1 0
Never 3 2

Six = Count of Encounter ( Where QuestionSet = DiabetesSi)
Twelve = Count of Encounter ( Where QuestionSet = DiabetesTw)

The sets are same except for the QuestionSet. I want to show them as
columns


MDX that I am trying

with
set [Template] as ''NonEmptyCrossJoin({[Person].[Person].members},
{[Question].&[SecondHandSmoke]}, {[Client].&[52]})''
-- This is the common set

member [Measures].[Six] as ''<What do I write here>' -- This should use
[QuestionSet].[DiabetesSi] for the measure total
member [Measures].[Twelve] as ''<What do I write here>' --This should
use [QuestionSet].[DiabetesTw] for the measure total


Select {[Answer].[Value].members} on rows,
{[Measures].[Six], [Measures].[Twelve]} on columns
from DM_Answer

I dont know what to write in the calculated members above so that the
output shows Six and Twelve as Columns

Please help

Milind


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Deepak Puri
 
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Default Re: MDX calculated members in Columns - 12-02-2005 , 08:17 PM






Hi Milind,

Not sure what you mean by "Count of Encounter", but here's my
interpretation of what you want:

Quote:
with
member [Measures].[Six] as
'([Measures].[Encounter, [QuestionSet].[DiabetesSi])'
member [Measures].[Twelve] as
'([Measures].[Encounter, [QuestionSet].[DiabetesTw])'

Select {[Answer].[Value].members} on rows,
{[Measures].[Six], [Measures].[Twelve]} on columns
from DM_Answer
where ([Question].&[SecondHandSmoke], [Client].&[52])
Quote:

- Deepak

Deepak Puri
Microsoft MVP - SQL Server

*** Sent via Developersdex http://www.developersdex.com ***


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Milind
 
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Default Re: MDX calculated members in Columns - 12-03-2005 , 03:05 AM



Perfect. Thanks alot Deepak!!!

Milind


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