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#1
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#2
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I can't use calculated members in data mining. I found information that I can use derived-member. I would like to calculate Sum(numberOfItems) in source column. Is it possible? Thanks all for help! Simon |
#3
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I'm not sure how exactly you model looks like. My first thought is to have a view defined in your data source and a filed of that view should be 'Sum(numberOfItems). Based on that view, build a relational model. Hope this helps... -- Raymond Balint [MS] This posting is provided "AS IS" with no warranties, and confers no rights. "Simon Abolnar" <Simon.Abolnar (AT) tscng (DOT) net> wrote in message news:eoYM%231dgDHA.3140 (AT) tk2msftngp13 (DOT) phx.gbl... I can't use calculated members in data mining. I found information that I can use derived-member. I would like to calculate Sum(numberOfItems) in source column. Is it possible? Thanks all for help! Simon |
#4
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I will better describe my situation: I have to calculate average sugar of grape received by different date. In SQL View I calculate: sugar*quantity (column) In OLAP I have member: quantity (which is sum of all quantity) I can easely calculate average sugar as: [Member].[sugar*quantity]/[Member].[quantity] How can I do this by using derived member? Is there a way to use calculate member in datamining? Thanks for help, Simon "Raymond Balint" <raymondb (AT) online (DOT) microsoft.com> wrote in message news:3f708907$1 (AT) news (DOT) microsoft.com... I'm not sure how exactly you model looks like. My first thought is to have a view defined in your data source and a filed of that view should be 'Sum(numberOfItems). Based on that view, build a relational model. Hope this helps... -- Raymond Balint [MS] This posting is provided "AS IS" with no warranties, and confers no rights. "Simon Abolnar" <Simon.Abolnar (AT) tscng (DOT) net> wrote in message news:eoYM%231dgDHA.3140 (AT) tk2msftngp13 (DOT) phx.gbl... I can't use calculated members in data mining. I found information that I can use derived-member. I would like to calculate Sum(numberOfItems) in source column. Is it possible? Thanks all for help! Simon |
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