dbTalk Databases Forums  

Custom Member Formula question

microsoft.public.sqlserver.olap microsoft.public.sqlserver.olap


Discuss Custom Member Formula question in the microsoft.public.sqlserver.olap forum.



Reply
 
Thread Tools Display Modes
  #1  
Old   
Derrick
 
Posts: n/a

Default Custom Member Formula question - 01-07-2004 , 03:12 PM






Is there a "this" type operator for custom member formula MDX?

What i would like to do is, for a leaf member in a dimension, have the
formula set it's value to half of what is stated in the fact table.
Basically

[Dimension].[*this*] * 0.5

Is that possible?

Thanks in advance!

Derrick



Reply With Quote
  #2  
Old   
Thierry [MS]
 
Posts: n/a

Default Re: Custom Member Formula question - 01-07-2004 , 03:59 PM






Not in AS 2000...

A This statement in 2000 would create a recursion, which is not allowed in
AS 2000.

If you want to do somehting like this you need to look at Calcuated Cell and
using PassOrder to reference the values form the same cell at a previous
PASS.


Thierry
This posting is provided "AS IS" with no warranties, and confers no rights.
"Derrick" <derrick1298 (AT) excite (DOT) com> wrote

Quote:
Is there a "this" type operator for custom member formula MDX?

What i would like to do is, for a leaf member in a dimension, have the
formula set it's value to half of what is stated in the fact table.
Basically

[Dimension].[*this*] * 0.5

Is that possible?

Thanks in advance!

Derrick





Reply With Quote
Reply




Thread Tools
Display Modes

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

vB code is On
Smilies are On
[IMG] code is On
HTML code is Off



Powered by vBulletin Version 3.5.3
Copyright ©2000 - 2012, Jelsoft Enterprises Ltd.