![]() | |
![]() |
| | Thread Tools | Display Modes |
#1
| |||
| |||
|
|
In postgreSQL 7.3.2 when I execute the following query select replace('test %400% result', 'result', 'ok'); it returns "test % ok" |
#2
| |||
| |||
|
|
On Tue, 13 Jul 2004, Nicolas Bottarini wrote: In postgreSQL 7.3.2 when I execute the following query select replace('test %400% result', 'result', 'ok'); it returns "test % ok" I think this was fixed in the 7.4 branch. |
#3
| |||
| |||
|
|
In postgreSQL 7.3.2 when I execute the following query select replace('test %400% result', 'result', 'ok'); it returns "test % ok" And If I Execute: select replace('test %%400%% result', 'result', 'ok'); it returns the correct result: "test %400% ok" If this is a known BUG please tell me because I need to fix this. Thanks Nicolas Bottarini |
![]() |
| Thread Tools | |
| Display Modes | |
| |