To reproduce:

create a table with a data type of varchar (50) and name it email

insert into this table the following values:
test1 (AT) anyemail (DOT) com

Execute the following statement:
SELECT CASE WHEN count(substring(email FROM '@.')) > 0 THEN count(substring(email FROM '@.')) ELSE 0 END, email FROM your_schema.your_table GROUP BY email;

Result with be equal to 1 / True. It should be 0 / False.

If you execute the above but replace '@.' with '@a' it will also return 1 / True is correct.

The only time it fails for me is if the @ is immediately followed by a period.

7.3.4 using psql via pgadminIII under cygwin.

Mike


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"Mike G." <mike (AT) thegodshalls (DOT) com> writes:
This is not a bug; it's a POSIX regular expression match, and it's
behaving exactly as it should ('.' matches any character).

The particular syntax substring(char-expression FROM char-expression)
is not defined by SQL99 --- their regular-expression construct requires
a third parameter (ESCAPE something). We have chosen to interpret it
as a POSIX regular-expression match. See
http://www.postgresql.org/docs/7.3/s...-matching.html

regards, tom lane

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