Hello,

I am doing a left outer join between a polygon table and a data table.
Everything
returns fine from this join as expected. However, there are cases where
there isn?t data for a given polygon and this return as the expected null
in the result set. I would like to utilize something like a case statement
to catch the nulls and return a ?more friendly? message. I have tried
unsuccessfully to use the following logic:

*Select case value_of_interest null then ?more friendly message? else
value_of_interest end*

*From poly_table left outer join data_table one poly_table.common_id =
data_table.common_id*

If someone could let me know where I am going wrong it would be greatly
appreciated.

Cheers,

Derek

Try that:

SELECT address, CASE WHEN value_of_interest IS NULL THEN 'more friendly
message' ELSE value_of_interest END value_of_interest
From poly_table left outer join data_table one poly_table.common_id =
data_table.common_id


--
Matheus de Oliveira




On Fri, Feb 3, 2012 at 10:45 AM, John Morgan <jdmorgan (AT) unca (DOT) edu> wrote:

Even better:

SELECT COALESCE(value_of_interest, 'more friendly message')
value_of_interest
From poly_table left outer join data_table one poly_table.common_id =
data_table.common_id

--
Matheus de Oliveira




On Fri, Feb 3, 2012 at 1:05 PM, Matheus de Oliveira <
matioli.matheus (AT) gmail (DOT) com> wrote:

Thanks Matheus. The coalesce method worked like a champ.

Cheers,
Derek

On 2/3/2012 10:09 AM, Matheus de Oliveira wrote:

--
Derek @ NEMAC