hi i m having the following problem...
i 'm starting a query with the count(*) function....
like: select aFieldName, count(*) as cant ........ ;

the thing is that i m doing a type check when i got the Result object...

with, result.types(j).base_type() =3D=3D typeid(std::string)=20
and with resultado.types(j).base_type() =3D=3D typeid(int)

both are arguments of two separated if statements...
my problem is that ONLY WHEN executing the query with the COUNT function...=
=20
i DO GET the value BUT it does NOT enter to neither of both if statements..=
..=20

which type is the value returned in the cant alias?? (or better to
say.. by the count(*) function?)

i hope you can give me a hint on this... i need to validate that types
so i m stucked there...
cheers and thanks in advance

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On Mon, Apr 25, 2005 at 11:45:49AM -0300, Nicolas Barrera wrote:
You could try printing the base_type to see what it is.

- Chris


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Hi Nicolas,

You emailed this a while ago, but I've been playing around with the type
info classes in mysql++... don't have any insights on your problem yet,
but what version of mysql C API (not mysql++) are you running?

(please reply to the list)

Thanks,
- Chris


On Mon, Apr 25, 2005 at 05:09:54PM -0300, Nicolas Barrera wrote:
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On 5/3/05, Chris Frey <cdfrey (AT) netdirect (DOT) ca> wrote:
I don't get it.., the C api for mysql isn't MYSQL++??
anyway... i 'm using.. mysql version 4.0.20, libsqlplus 1.0.7, mysql++ 1.7.=
32

=20

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Nicolas Barrera wrote:
No, MySQL++ is only a wrapper around the C API; everything mysql++ does is
basically just a lot of convenience to make the C++ programmer's life easier.

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On 5/3/05, Earl Miles <merlin (AT) logrus (DOT) com> wrote:
ok sorry i m not awared of that... :S , i ve just joined this project
and i got not much information of all that..., so.. where could i
check the real mysql api ?

thanks...

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Nicolas Barrera wrote:

You've already answered the question...it's the same as your MySQL
version number. (Oh, I suppose the API has a different internal version
number, but the MySQL version number suffices.)

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