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#21
 
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Re: How does your MOD() function work? -
06-12-2010
, 12:45 PM
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On 2010-06-11, Lennart Jonsson<erik.lennart.jonsson (AT) gmail (DOT) com> wrote: On 2010-06-11 01:03, --CELKO-- wrote: [...] Otherwise, the result is the unique non-negative exact numeric value r with scale zero such that 1)r has the same sign as n. For negative n should r be positive or negative? |
that only positive n are allowed. Why did they make it so complicated
and error prone? Talk about design by committee...
Rereading the criteria I believe they accidentally inserted
"non-negative" in the sentence above. Otherwise it would not make any
sense to include 1 and talk about an "absolute value" in 2.
So, finally to answer Lennart's question I believe the _intention_ of
the standard was that for negative n r should be negative as well.
Quote:
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from the above I think that version of the standard only allows for whole number n |
http://en.wikipedia.org/wiki/Whole_number
:-)
Kind regards
robert
--
remember.guy do |as, often| as.you_can - without end
http://blog.rubybestpractices.com/
#22
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MOD (12, 5) = 2 MOD(-12, 5) = -2 MOD (-12, -5) = -2 MOD (12, -5) = 2 MOD (NULL, 5) = NULL MOD (NULL, NULL) = NULL MOD (12, NULL) = NULL MOD (12, 0) = NULL MOD (-12, 0) = NULL MOD (0, 5) = 0 MOD (0, -5) = 0 MOD (0, 0) = NULL |
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