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Mikito Harakiri
 
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Default bag intersection definition - 09-05-2003 , 07:40 PM






The "standard" definition when

{1,1,1} intersect {1,1} = {1,1}

is just plain naive. Given that

intersection = projection * equality selection * cross product

(operator multiplication notation is right-associate)

the definition should be:

{1,1,1} intersect {1,1} = {1,1,1,1,1,1}







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Jan Hidders
 
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Default Re: bag intersection definition - 09-09-2003 , 04:03 PM






Mikito Harakiri wrote:

Quote:
The "standard" definition when

{1,1,1} intersect {1,1} = {1,1}

is just plain naive. Given that

intersection = projection * equality selection * cross product

(operator multiplication notation is right-associate)

the definition should be:

{1,1,1} intersect {1,1} = {1,1,1,1,1,1}
Yeah, but then you lose the equation that X intersect X = X. Anyway, this is
largely esthetics.

-- Jan Hidders


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  #3  
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Mikito Harakiri
 
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Default Re: bag intersection definition - 09-09-2003 , 04:33 PM



"Jan Hidders" <jan.hidders (AT) pandora (DOT) be> wrote

Quote:
{1,1,1} intersect {1,1} = {1,1,1,1,1,1}

Yeah, but then you lose the equation that X intersect X = X. Anyway, this
is
largely esthetics.
X union X = X

is not valid for bags either. Dual operations must have (or must have not)
dual identities.




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