hi every body


here is my function to get last day of the month. but it causes error while executing.

please help

/*
This function returns the last day of the given date's month.
-- Logic --
extract month and year from the given date
build a date of next month by concatnating these values and any day* ( 1- 28)
then substract the given day* from the concatnated date.
*/
declare
dteGivenDate date;
intGivenMonth integer;
intGivenYear integer;
intNextMonth integer;
dteLastDay date;
strTmp varchar;
dteTmp date;
begin
--dteGivenDate:='12-03-2004';
dteGivenDate:=$1;
intGivenYear:=date_part('year',timestamp dteGivenDate);
intGivenMonth:=date_part('month',timestamp dteGivenDate);
intNextMonth:=intGivenMonth + 1;
if intNextMonth >12 then
intNextMonth:=1;
intGivenYear:=intGivenYear+1;
end if;
strTmp:= intGivenYear || '-' || intNextMonth || '-' || '10'; -- here we can give any value insted of 10 ranging from (1-28)
dteTmp:= to_date(strTmp,'YYYY MM DD');
dteLastDay:= date dteTmp - 10;
return dteLastDay;
end;



****************

is there any other alternative to this function like a builtin function like last_day ...

sincerely rajesh


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On Sat, Oct 02, 2004 at 11:41:37PM -0700, Rajesh nalankal wrote:
This should get you started:

SELECT date_trunc('month', CURRENT_DATE + INTERVAL'1 month') - INTERVAL'1 day';

--
Michael Fuhr
http://www.fuhr.org/~mfuhr/

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