Re: having clause question

#1

On Sat, 30 Oct 2004 15:17:16 -0700, Shane Wegner
<shane-keyword-pgsql.a1e0d9 (AT) cm (DOT) nu> wrote:

Quote:

Hello,
(...)
I want to retrieve any last names with more than 1
occurence in the table. Under MySQL, this query does the
trick.
select lastname,count(*) as c from names group by lastname
having c > 1;

But under PG, it errors out
ERROR: column "c" does not exist

Is it possible to do a query like this with PostgreSQL?

select lastname,count(*) as c from names group by lastname having count(*) > 1;

HTH

Ian Barwick
barwick (AT) gmail (DOT) com

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#2

Ian Barwick <barwick (AT) gmail (DOT) com> writes:

Quote:

On Sat, 30 Oct 2004 15:17:16 -0700, Shane Wegner
shane-keyword-pgsql.a1e0d9 (AT) cm (DOT) nu> wrote:
Under MySQL, this query does the trick.
select lastname,count(*) as c from names group by lastname
having c > 1;

Is it possible to do a query like this with PostgreSQL?

select lastname,count(*) as c from names group by lastname having count(*) > 1;

Just to expand on that: MySQL's abbrevation is not legal SQL, and it's
not even very sensible, because logically speaking the SELECT output
list is only evaluated after (and if) the HAVING clause succeeds.
So it makes no sense for the HAVING clause to refer to SELECT values.

Postgres does optimize the case of multiple identical aggregate-function
invocations in a query, BTW, so the apparent inefficiency is not real.

regards, tom lane

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Re: having clause question

comp.databases.postgresql.general comp.databases.postgresql.general

Re: having clause question - 10-30-2004 , 05:36 PM

Re: having clause question - 10-30-2004 , 06:12 PM