I have 2 existing tables in my db:

iss=> \d pollgrpinfo
Table "public.pollgrpinfo"
Column | Type | Modifiers
---------------+------------------------+-----------
pollgrpinfoid | integer | not null
pollgrpid | integer | not null
name | character varying(100) |
descript | character varying(200) |
Indexes:
"pollgrpinfo_pkey" primary key, btree (pollgrpinfoid)
"pollgrpinfo_pollgrpid_key" unique, btree (pollgrpid)

iss=> \d notpoll
Table "public.notpoll"
Column | Type | Modifiers
-------------+------------------------+---------------------
notpollid | integer | not null
pollgrpid | integer |
notgroupsid | integer |
alerting | character(1) | default 'y'::bpchar
disuser | character varying(50) |
distime | integer |
alertingcom | character varying(200) |
Indexes:
"notpoll_pkey" primary key, btree (notpollid)
"notpoll_pollgrpid_key" unique, btree (pollgrpid)
"notpoll_alerting_index" btree (alerting)
Triggers:
"RI_ConstraintTrigger_2110326" AFTER INSERT OR UPDATE ON notpoll
FROM notgroups NOT DEFERRABLE INITIALLY IMMEDIATE FOR EACH ROW EXECUTE
PROCEDURE "RI_FKey_check_ins"('notgroups_exists', 'notpoll',
'notgroups', 'UNSPECIFIED', 'notgroupsid', 'notgroupsid')

I am trying to add a foreign key to the notpoll table

iss=> alter table notpoll add constraint pollgrp_exists foreign
key(pollgrpid) references pollgrpinfo on delete cascade;
ERROR: insert or update on table "notpoll" violates foreign key
constraint "pollgrp_exists"
DETAIL: Key (pollgrpid)=(7685) is not present in table "pollgrpinfo".

I have verified that the information is in the pollgrpinfo table:

iss=> select * from pollgrpinfo where pollgrpid=7685;
pollgrpinfoid | pollgrpid | name | descript
---------------+-----------+------+----------
767 | 7685 | HTTP |
(1 row)


I could use a suggestion on how to proceed in troubleshooting the error
message. I am running 7.4.5

Thanks,
Woody

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TIP 9: the planner will ignore your desire to choose an index scan if your
joining column's datatypes do not match

george.woodring (AT) iglass (DOT) net ("George Woodring") writes:

When expressed as "FOREIGN KEY (foo) REFERENCES mytable" postgresql
assumes that foo references the PRIMARY KEY for table mytable. If you
are not referencing the primary key, you need to tell postgresql which
column e.g. FOREIGN KEY (foo) REFERNCES mytable(foo).


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