(Pardon me for asking a very basic question. I have come back to SQL
Server after five years of Oracle, and my memory is a tad rusty).

I have a bit of SHOW_PLAN output that I believe that I understand, but
I would appreciate your comments if I am wrong.

I have a requirement to produce a list of the primay key values in a
table along with the total count of rows:

Given this table and contents:

create table taCountDemo (ID char(01) primary key, someData
varchar(50));

insert into taCountDemo (ID,somedata)
select 'a', 'aaaa'
union
select 'b', 'bbbb';

the results should be:

ID counter
---- -----------
a 2
b 2

(don't wonder why - there's a SAS application on top which means that
ordinary rules of logic don't apply)

This is the query that I'm using:

select ID
, cnt.counter
from taCountDemo
cross join
(select counter
from ( select count(*) as counter
from taCountDemo
) as i
) as cnt;

The SHOW_PLAN output is like this:


My understanding of this is that the count(*) is only executed ONCE,
and that the nested loop then combines the result (EXPR1006) with all
keys obtained by scanning the primary key index. Or in other words
that the single-"row" result of the count(*) is chosen as the "table"
that drives the loop.

Is that correctly understood?

Thanks for your input

Bo Brunsgaard

bbcworldtour (AT) hotmail (DOT) com wrote:

What about:

SELECT ID, (SELECT Count(*) FROM taCountDemo) as counter
FROM taCountDemo

?

Execution plan will be exactly the same but IMHO it looks much simpler.



Yes, you're completely right.


--
Best regards,
Marcin Guzowski
http://guzowski.info

Maybe I am wrong but I think it is other way around. It puts the sql
statement in a nested loop and count(*) is executed many times.