Hi,

I have a sql query like this

select avg([mycolumn]) from data where date > '1/5/08' and date <
'1/10/08'
group by [mycolumn]
order by [mycolumn] desc

If all values within that average are numbers, I'm fine. If it's a 0
(not a null, a 0) it doesn't get averaged in. For instance, values
0,1,2 should produce an average of 1.

(0+1+2)/3 = 1.

But sql is returning a value as if my 0's were nulls and not factored
in:

(1+2)/2 = 1.5

Does anyone know why this is happening and how to fix it?

"lee.richmond" wrote:
Lee,

a simple test does not replicate your problem. The simple script below
returns an average of 1.0 on SQL Server 7.0, 2000 and 2005.

create table #t(v decimal(3,2))
insert into #t values (0)
insert into #t values (1)
insert into #t values (2)
select avg(v) from #t
drop table #t

If the problem persists, then please post a repro script and the version
of SQL Server you are using.

--
Gert-Jan

On Wed, 30 Jan 2008 13:18:59 -0800 (PST), lee.richmond wrote:

Hi Lee,

I was unable to reproduce this behaviour. Can you post some code (i.e. a
full repro script: CREATE TABLE statements, INSERT statements, and the
offending query) that I can run on my test server that does show this
behaviour on your machine?

I suspect something else is biting you, but I have to see a repro to
find out what it is.

--
Hugo Kornelis, SQL Server MVP
My SQL Server blog: http://sqlblog.com/blogs/hugo_kornelis

Thanks for the quick responses. I know what was happening here but
unfortunately it brings me to another problem.

This was a problem with a group by:

select distinct [kw id], avg([bulk sd cr]) as [bulk SD] from data$
group by [kw id], [bulk sd cr]
order by [bulk sd] desc

Screwed up my averages. For it to be proper, it's

select distinct [kw id], avg([bulk sd cr]) as [bulk SD] from data$
group by [kw id]
order by [bulk sd] desc

However, the reason I had [bulk sd cr] in the group by in the first
place is because I have a case statement for sorting like:

order by case when @sortvar = 1 then [bulk sd cr]
when @sortvar = 2 then [kw id]
end desc

My case statement only works if I have all the fields in that case
statement also in the group by. This doesn't make sense to me - why
should the order by work fine when it's not a case statement, but
break when it is a case statement?




On Jan 30, 4:52 pm, Hugo Kornelis
<h... (AT) perFact (DOT) REMOVETHIS.info.INVALID> wrote:

lee.richmond wrote:

Presumably the original statement looked like this:

select distinct [kw id], avg([bulk sd cr]) as [bulk SD] from data$
group by [kw id]
order by case when @sortvar = 1 then [bulk sd cr]
when @sortvar = 2 then [kw id]
end desc

which certainly won't work when @sortvar = 1, so SQL Server probably
decides to toss it out entirely.

Does this work, instead? Is it what you intended?

select distinct [kw id], avg([bulk sd cr]) as [bulk SD] from data$
group by [kw id]
order by case when @sortvar = 1 then avg([bulk sd cr])
when @sortvar = 2 then [kw id]
end desc

Thanks for the reply Ed. That's definitely what I have been trying to
do but it isn't working, which is what led me to get my convoluted
incorrect code above. The problem is that the case statement, and no
other changes, break this. So:

select distinct [kw id], avg([bulk sd cr]) as [bulk SD] from data$
group by [kw id]
order by avg([bulk sd cr]) desc
end

Works perfectly. But change nothing but make the order by a case
statement:

select distinct [kw id], avg([bulk sd cr]) as [bulk SD] from data$
group by [kw id]
order by case when @sortvar = 1 then avg([bulk sd cr])
when @sortvar = 2 then [kw id] end desc
end

End I get an error saying "ORDER BY items must appear in the select
list if SELECT DISTINCT is specified." This doesn't make sense to me
because the only change is a case statement. Do you know why this is
happening?

lee.richmond (Richmolj (AT) gmail (DOT) com) writes:
But that is a vital change. Read the error message again: do you see the
ORDER BY item in the SELECT list?

Then again, what is that DISTINCT doing there in the first place? I can't
see that it fills any function. Since you have a GROUP BY there cannot
be any duplicates anyway.

However, I think a nicer way to write it is:


SELECT [kw id], {bulk SD]
FROM (SELECT [kw id], avg([bulk sd cr]) as [bulk SD]
from data$
group by [kw id]) AS x
ORDER BY case when @sortvar = 1 then [bulk SD]
when @sortvar = 2 then [kw id]
end desc

That thing in parentheses is a derived table. Logically, it is a temp
table table within the query, but it's not computed that way; the
optimizer will optimize the query as a unit, so there is no overhead.


--
Erland Sommarskog, SQL Server MVP, esquel (AT) sommarskog (DOT) se

Books Online for SQL Server 2005 at
http://www.microsoft.com/technet/pro...ads/books.mspx
Books Online for SQL Server 2000 at
http://www.microsoft.com/sql/prodinf...ons/books.mspx

That actually makes perfect sense to me, good idea. I'll give it a
try. Thanks!

Erland Sommarskog wrote:

Lee, what are the data types for [kw id] and [bulk SD]? If they're
different, then IIRC the CASE will run into weird type-conversion
issues as well.