I've seen the following several times in .def files:

LIBRARY foo
EXPORTS
foo@24
foo = foo@24

What is the @24 for?

Thanks!

Wendy
School of Computing
Queen's University
Kingston, ON

Hi Wendy,

The @24 is the size of the parameters passed to foo. For instance given
functions:

int foo(int a, int b)
int foo2(int a)
int foo3(int a, char b)

You would get foo@8, foo2@4 and foo3@8 (in this case the sizeof(char) would
be rounded up to the WORD size).

take a look at this site it gives a good explanation:
http://www.codeproject.com/cpp/calli...emystified.asp

--
Garfield A. Lewis
DB2 UDB Development,
IBM Canada Laboratory


"Wendy Powley" <wendy (AT) cs (DOT) queensu.ca> wrote

Thanks a lot Garfield! That explains why my code isn't compiling &
answers a question I've been wondering about for a while!

Wendy

Ok, can you explain this to me? (This is code taken from an app that
compiles & works fine for me).

I have the following function definition:


create procedure foo ( in parm1 smallint,
in parm2 smallint,
out parm3 varchar(150),
out parm4 smallint,
out parm5 smallint,
in parm6 int)
language c
parameter style general
external name 'my_foo!foo'
fenced;

and the .def file looks like:

LIBRARY foo
EXPORTS
foo@24
foo = foo@24

How do we get 24 for the size of the parameters listed above?

Thanks again!

Wendy
~