Rich,
Do you mean, transform the ten reps of FieldA into ten records of FieldB?
That is accomplished using an import that splits repetitions, usually.
A calculation by itself cannot create records.
If the two tables were related, you could also use, in FieldB of TableB
GetRepetition ( TableA::FieldA; Get ( RecordNumber ))
which will pull across the matching repetition from FieldA of TableA. (But
only the first record returned by the relationship!)
Bill
"Rich Sagall" <rich.sagall (AT) pobox (DOT) com> wrote
Quote:
I have FM8 Pro Advanced. I have ieldA with 10 repetitions. I want to
write a script to create fieldBwith data from all 10 of the repetitions
of fieldA. I can do this by writing out 10 set steps to create fieldB,
but that's an inelegant way to do.
I was told FM8 lets you do a lot more with repeating fields. Is this
true and, if so, how would I accomplish task in an elegant way?
Thanks,
Rich |